Question

5. The equilibrium constant (K) for the formation of methyl benzoate from methanol and benzoic acid at 25°C is 3.77. Use the equation for the equilibrium constant to calculate the theoretical yield of methyl benzoate for the following conditions. (6 marks) a) With equal initial amounts of the reactants (1 mole of each reactant) b) With a threefold (x 3) excess of methanol (1 mole of benzoic acid and 3 moles of methanol) 6. Suggest a chemical reaction (include structures of reactants and products), which could lead to the formation of another ester, sec-butyl 2-phenylethanoate. (2 marks)

Answer 1

I we shall set up an icf table. Phcoocha jkt a atter Ph coolt & etgoh 44+ H2O s. lode e to teg . keq or or lhe : 3.44 (given) 194 l au-laude de y hus; Hence; methyl theoretical yield is 0.66 moles of thougt bengoate bercentage theoretical yield: 661 also ILE table is needed i. PhcooH & CH₃OH - Phcooch & H₂O 6 Here - 7:4 7. leg 1- i-de 3(1-x) 3l1-ke) a 9.99 ) - . 11:31 2 Key = 3 11-dele 1 or de : 3.36 = de = 3.36 = 3.36 de or 4.36 de = 8.36 =) de = 0.7713 Theoretical bercentage yield = 79.137.. First of all, we need to know the structure - etetty 1 6. w Ph-etq-e-o rec- butye 2-phenye ath ano ate=) M Estonification easily fischer by very HS We can prouss. synthesige as below: Ph-Cty - 120-4th-CH HS Hq sou , reflun w f OH - CHy-ef. Ph CH, CooH ☺ Hope this was helpful.