Solve and label the HNMR and CNMR
You have not given CNMR!!!
I can solve only 1HNMR.
Peak at 1.8 is smallest peak, take it for 1 proton intensity.
Peak at 0.9 is doublet of intensity of 6 protons and value is less than one that mean we have 2 CH3 group which have only proton in neighbor
Peak at 1 is triplet of intensity of 3 protons so it will be 1 CH3 group and it will have two protins in neighbor.
Peak at 1.25 is multiplet of 2 protons intensity, so it will be 1 CH2 group.
Peak at 1.5 is again multiplet of 2 protons intensity so it will also1 CH2 group.
Peak at 1.8 is for 1 proton so it will be CH group.
Peak at 2.4 is triplet for 2 protons that mean it is CH2 group attached with two protons neighbor. This value also indicate that this CH2 attach with carbonyl carbon.
Peak at 3.8 is doublet of 2 protons intensity that mean it is CH2 group attached with one proton in neighbor. This value also indicate that the CH2 group attached with -O of ester.
Finally structure of compound is
Solve and label the HNMR and CNMR Unknown #2 CgH180 3.5 3.0 2.5 2.0 1.5 1.0...
Please label and interpret the following HNMR peaks of an unknown compound. Be sure to include the complete calculation of the peak integration, splitting patterns, and identify the chemical formula of the unknown compound. Also, there is an impurity peak at 3.4 ± 0.2 ppm. No title BRUKER Carzent Data Paxaetera 20290307 SWH F IDRES o.220503 sec 0.0L500000 sec 400-1331 926 M 22 - Prscessing pazanet 32768 400.1299740 Mi 8 5.5 5.0 4.5 4.0 3.5 3.0 2.5 2.0 1.5 1.0...
1. Formula C,H4O 4000 3500 2H 3H 3H 2H 2H 2H 1.5 2.0 4.5 3.5 3.0 2.5 1.0 PPM 4.0 20es 0*250 T6 61 '8201 LSIT 60 99T 90 01L1 e'SPLT Or'8282 1. Formula C,H4O 4000 3500 2H 3H 3H 2H 2H 2H 1.5 2.0 4.5 3.5 3.0 2.5 1.0 PPM 4.0 20es 0*250 T6 61 '8201 LSIT 60 99T 90 01L1 e'SPLT Or'8282
Please help me interpret the proton NMR of this unknown aldehyde. ZACH RIA A3 2 -1400 -1300 -1200 -1100 1000 -900 -800 -700 -600 -500 400 300 -200 -100 -100 -5.5 4.5 -5.0 -3.5 -4.0 -2.5 -3.0 -1.5 -2.0 -0.5 -1.0 f1 (ppm) 0.5 0.0 1.5 1.0 2,5 2.0 4.0 3.5 3.0 Adtyd SE 910- 660-h ar ZACH RIA A3 2 -1400 -1300 -1200 -1100 1000 -900 -800 -700 -600 -500 400 300 -200 -100 -100 -5.5 4.5 -5.0 -3.5...
Fill in the CNMR and HMNR table for the corresponding spectrscopy charts. Major Component CDCL3T 240 120 57 Major Component -180 -7.26Chloroform- -170 160 7.40 -5.81 150 140 -130 120 -110 -100 1.00 6.5 6.0 7.0 5.5 5.0 4.5 4.0 3.5 f1 (ppm) 3.0 2.5 2.0 1.5 1.0 0.0 0.5 NMR 1C Shift (8) | H Shift (6) 'H Integration | 'H Splitting Assignment
NMR & IR post lab question help! NMR and IR 4.5 4.0 3.5 3.0 2.5 2.0 1.5 1.0 0.5 ppm IH The 'H NMR for the unknown C: 20 7.5 7.0 6.5 6.0 6.5 5.0 4.5 4.0 3.5 3.0 25 20 519 05 Proton peak Integration Chemical Shift (ppm) Neighbors (m) Splitting pattern (+1) report as singlet/doublettripletlets. C must be an aliphatic alcohol. There is a strong O-H stretch in the IR and zero degrees of unsaturation. The remaining structure...
Determine structure of unknown compound by deducing the formula and analyzing the spectra. Part C:S IR/HNMR/CNMR Unknown #93 MW=134 AMU / ring SOC-H dromul 5,311 - Overlapping Signals, 4 1,34 HEP-11-24 ppm 4 Signals 120-160 ppm 200 180 20-0-075 160 240 120 80 40 20 100 pon
IR/HNMR/CNMR Unknown #102 MW-110 AMU 0 -H C=0 Wavenumber(em-1) Broads.s.2 3 overlapping signals, 4 FM EN ppm 20 0 200 180 160 12010030604020 rpm
Draw the structures of the Compounds 2.0 3.64 Unsat. Index = (2C+2-H-X +N)/2 = 1.5 1.06 6.86 7.00 d = 2.44 ppm, Compound 18a. C, H, N quartet, 2H 1.0 7.02 6.84 2.43 2.45 1.08 1.04 a = 7.01 ppm, c = 3.64 ppm, b = 6.85 ppm, 0.5 doublet, 2H doublet, 2H singlet, 2H e = 1.06 ppm, 2.41 2.47 triplet, 3H 8, ppm 0.0 8.0 7.5 7.0 6.5 6.0 5.5 5.0 4.5 4.0 3.5 3.0 2.5 20 1.5...
5.0 69 4.5 68 3.5 3.0 $ 2.5 2.0 67 65 64 63 61 1.0 0.5 3.0 3.5 4.0 4.5 5.0 5.5 6.0 6.5 7.0 UNEMPLOYMENT RATE (Percent)
Interpret the CNMR, HNMR and IR spectrum to determine the identity of the unknown compound. MP = -56 degrees C and BP = 131 degrees C 13C NMR 220 220 200 180 180 160 140 120 PPM 100 80 60 40 20 0 El-MS: 100.1 MP = -56 °C BP = 131 °C 1H NMR 2 4 3 8 PPM SciFinder® οοτ 001 οε 08 TRANSMITTANCE [%] 60 40 20 40ο 4000 38ο 3500 οοο 3000 εοο οοο 2500 2000...