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Part C In Part A. you found the amount of product (1.80 mol P-0s ) formed from the given amount of phosphorus and excess oxyg
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Answer #1

balanced Chemical reaction is as follows;
P4 + 5 O2 => 2 P2O5

then

P4: 112 g = 112 g/ 124 g/mol – 0.903 mol

O2: 112 g = 112 g / 32 g/mol = 3.5 mol

the,calculate the amount of P2O5 produced.

2.5 mol of O2 will react with 0.7 mol of P2O5 to produce 1.4
mol of P2O5.So,

1.4 * (31*2 + 16*5) = 198.8 g

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