Question

please answer the 3rd one??‍♀️

86% Patterns of inheritance Problems (21 Insert Draw Layout Review View UA. AETA Arial DOMINANCE 3. In some chickens, the gene for feather color is controlled by codominance. The allele for black is B and the allele for white is W. The heterozygous phenotype is known as erminette. a. What is the genotype for black chickens? b. What is the genotype for white chickens? c. What is the genotype for erminette chickens? d. If two erminette chickens were crossed, what is the probability that: i. They would have a black chick? ii. They would have a white chick? iii. They would have an erminette chick? -_ % 4. CHALLENGE In shorthorn cattle, coat color may be red, white, or roan. In roan cattle, their coats are a mixture of red and white hairs, although the animals appear a light rust color from a distance. Show a cross between a roan bull and a red cowe and give the expected genotype and phenotype. The Yes

Answer 1

Codaminace in the genetics states is alternate to mendel's rule where in that there are alles which is one will be dominant to other recessive alle but in Codaminance is when both alles of the genotypes are seen in the particular organism or phenotypic form.

a) the genotype of the black chicken will be : BB.

b) the genotype of the white chicken will be : WW

c) where it codaminant and there are same alles in them there will be no masking of recessive alles in them so the genotype of erminette chickens will be : BW.

d) Now there will be punnet square for the f1 generation from their parental phenotype and genotype

B W

B

BB( Black)	BW ( codaminant)
BW( codaminant)	WW( white)

W

if two erminette chickens where crossed the probability will be that:

a) they would have black chicken probability will be : 25%

b) they would have white chicken probability will be : 25%.

c) they would have erminitte chicken if black chicken and white chicken are crossed the probability will be : 100%

parents: BB* WW

B B

W

BW	BW
BW	BW

W