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Use the given statistics to complete parts (a) and (b). Assume that the populations are normally distributed. (b) Construct a

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Answer #1

The test statistic is:

T1 T2 48.1-45.8 2.3 7.12 10.42 2.89461 ↓ 17

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The degree of freedom is:

df = min(n1-1.112-1) = mìn(25-1, 17-1) 16

For 99% confidence level, critical value of t is t* _ 2.921.

The 99% confidence interval is:

10.42 그 + _ = (48.1- n1 n2 45.8) ± 2.921 /212 (Fi-F2) ± t* 25 17 2.3 ± 2.921 (2.86461) = 2.3 ± 8.45 or (-6.15, 10.75)

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