< Chapter 13 Homework Vertical Mass-and-Spring Oscillator Constants I Periodic Table A block of mass m-...
A block of mass mmm= 3.00 kg is attached to the end of an ideal spring. Due to the weight of the block, the block remains at rest when the spring is stretched a distance hhh= 8.00 cm from its equilibrium length. (Figure 1)The spring has an unknown spring constant k. Take the acceleration due to gravity to be g = 9.81 m/s2m/s2 . Suppose that the block gets bumped and undergoes a small vertical displacement. Find the resulting frequency...
1) A block of mass m = 0.52 kg is attached to a spring with
force constant 119 N/m is free to move on a frictionless,
horizontal surface as in the figure below. The block is released
from rest after the spring is stretched a distance A = 0.13 m.
(Indicate the direction with the sign of your answer. Assume that
the positive direction is to the right.)
(a) At that instant, find the force on the block. N
(b)...
Review l Constants ! Periodic Table Part A A block with a mass of 0.30 kg is attached to a horizontal spring The block is pulled back from its equilibrium position until the spring exerts a force of 1.1 N on the block When the block is released, it oscillates with a frequency of 1.2 Hz How far was the block pulled back before being released? Express your answer with the appropriate units. alne Units Submit
Constants Periodic Table Correct A 1.10 kg block is attached to a spring with spring constant 17.0 N/m . While the block is sitting at rest, a student hits it with a hammer and almost instantaneously gives it a speed of 46.0 cm/s What are ▼ Part B The block's speed at the point where x= 0.100 A? Express your answer with the appropriate units. Value Units Previous Answers Request Answer X Incorrect; Try Again; 5 attempts remaining
A block of mass m = 1.07 kg is attached to a spring with force constant 134.0 N/m. The block is free to move on a frictionless, horizontal surface as shown in the figure. The block is released from rest after the spring is stretched a distance A = 0.15 m to the right. What is the potential energy of the spring/block system 0.28 s after releasing the block?
A block of mass m = 1.23 kg is attached to a spring with force constant 157.0 N/m. The block is free to move on a frictionless, horizontal surface as shown in the figure. The block is released from rest after the spring is stretched a distance A = 0.11 m to the right. What is the potential energy of the spring/block system 0.28 s after releasing the block?
A block of mass m = 0.57 kg is attached to a spring with force constant 144.0 N/m. The block is free to move on a frictionless, horizontal surface as shown in the figure. The block is released from rest after the spring is stretched a distance A = 0.16 m to the right. What is the potential energy of the spring/block system 0.20 s after releasing the block? J
Review 1 Constants Periodic Table PartA A 0.800 kg block is attached to a spring with spring constant 16 N/m. While the block is sitting at rest, a student hits it with a hammer and almost instantaneously gives it a speed of 43 cm/s What is the amplitude of the subsequent oscillations? Express your answer in centimeters Submit Part B What is the block's speed at the point where z = 0.25/47 Express your answer in centimeters per second.
A block of mass m = 0.59 kg is attached to a spring with
force constant 128 N/m is free to move on a frictionless,
horizontal surface as in the figure below. The block is released
from rest after the spring is stretched a distance A = 0.13
m. (Indicate the direction with the sign of your answer. Assume
that the positive direction is to the right.) (a) At that instant,
find the force on the block. N (b) At that...
Constants Periodic Table A spring (80 N/m) has an equilibrium length of 1.00 m. The spring is compressed to a length of 0.50 m and a mass of 2.1 kg is placed at its free end on a frictionless slope which makes an angle of 41° with respect to the horizontal. The spring is then released. 0.50 m 0 = 41° Part A If the mass is not attached to the spring, how far up the slope from the compressed...