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10-5 Estimate the as-discarded energy content for a waste (a) with the composition given in Prob. 10-3. 10-6 Derive an approximate chemical formula for a waste (a) with the composition given in Prob. 10-3

Answer 1

CHARACTERIZATION OF SOLID WASTE Table 1 Ultimate Analysis of the Combustible Components in Household MSW Component Percent by Weight (Dry Basis) Carbon Hydrogen Oxygen Nitrogen Sulfur | Ash Organic Paper 43.5 6.0 44.0 0.3 0.2 6.0 Plastics 60.0 7.2 22.8 - - 10.0 Food wastes 48.0 6.4 37.6 2.6 0.4 5.0 Yard wastes 47.8 6.0 38.0 3.4 0.3 4.5 Textiles 55.0 6.6 31.2 0.15 2.5 Rubber 78.0 10.0 T T 4.6 2.0 0.2 . 0.1 10.0 1.5 Wood 49.5 6.0 0.1 42.7 Inorganic Inorganic 0.4 Glass 10.5 10.1 0.1 <0.1 98.9 Metals 4.5 0.6 4.3 <0.1 90.5 Dirt, ash, etc. 26.3 3.0 2.0 0.5 0.2 68.0 Municipal 15-30 2-5 12-24 0.2-1.0 0.02-0.1 solid wastes

By the use of above composition table divide waste in terms of Carbon, Sulfur, ovitrogen et let 100 kg of Dory solid Waste So, for given percent by mass 1% = 1kg Now [cardboard Paper] Components Dry Mass Carbon Hydrogen oxygen Nitrogen sulfur Food waste Paper cardboard 5.76 17.4 3.48 17.6 0.768 2.4 0.48 10.288 4.512 0.312 0.12 3.520.024 0.912 - 10.048 10.08 0.016 Plastic 2.4 Yard waste 7.17 0.9 5.7 0.51 0.045 wood 2.475 0.3 2.135 0.01 0.005 16 Inerts Glass 10.08 38.765 0.016 10.064 0.016 5.152/34.443 0.992 I lookg 10.194 Now, for energy content use Dealong formula :-) 3376 + 1419 (H₂ - 0.125 0₂) +935 +23N => 337138.765) +141915:152 -0.125(34.443) + 9310.194) + 2366.992) -> |14306 MJ/kg

Element : chloins Mass :- 138.765 5.152 34.443 0.492 10.194 Ratio - 1200/26-5|178 S T I Take Sulphur => 1 then cikio, nis are modified by - dividing them by 0.194. Molecular C200 H27 0 178 Ng Si formula :-