Question

18.10(b) If 175 cm of carbon dioxide effuses through a small hole in 255 seconds, how long wil it take the same volume of sulfur dioxide to effuse under the same temperature and pressure?

Answer 1

To calculate the relative rate, of effusion of CO2 and SO2 gas uses following equation Rate of effusion of Co Rate of effusion of SO, SO co Here, Ms。, = Molar mass of SO2; 64.066 g / mol Mco. Molar mass of CO,; 44.01 g /mol Now put these values in the above equation to calculate the relative rate, as molecules per second of the molecules of carbon monoxide and hydrogen: Mso Rate of effusion of CO, Rate of efusion of SO, Co2 Rate of effusion of CO Rate of efusion of SO, 4.066 g LmoT 44.01 g /mol The relative rate, as molecules per second of the molecules CO2 and SO2 is .

r1/r2 = (v1/t1) / (v2/t2) = square root of (M2/M1)
where r1 is rate of effussion of gas CO2

r2 is rate of effussion of gas SO2
v1 = volume of gas effussed for gas CO2
v2 = volume of gas effussed for gas SO2
t1 = time taken by gas CO2
t2 = time taken by gas SO2

Then;

r1/r2 = (v1/t1) / (v2/t2)

1.21 =( 175 cm^3/ 255 seconds ) / (175 cm^3/ t2 seconds )

t2 seconds = 1.21*255

= 308.55 seconds