Question

This problem is related to the activity of 14 C in a living organism and radioactive dating for a dead organism. The half-life of 1.4 C is 5,730 years and assume that in a living organism there is one atom of 1.4 C for every 8.3x 1011 atoms of b?C. Given: the molar mass of b? C is 12 gram/mol and there are 6.02 x 1023 atoms in one mole of a substance. Determine the number of 14 Catoms present for every gram of 5. C in a living organism. 3.02 x 1010 atoms 6.04 x 1010 atoms 9.02 x 105 atoms 7.08 x 1012 atoms 1.13 x 106 atoms

Answer 1

Total No. of 126 atoms atoms in Ig carbon 12 = NNA As there is only ! 6 only I 14 c atom for every 8.3410" alors No. of 14 c antony = e 8.34101 No of the for every grams of 126 = (mol) Imol (6-02X1023) No. of atoms = 6•0481010 atoms Am 8. 3x1011

Hope this helps...