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Suppose you are a researcher in a hospital. You are experimenting with a new tranquilizer. You collect data from a random samc) Construct a 99% confidence interval for the population mean length of time. Enter your answer as an open-interval (i.e., p

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Answer #1

Ans:

a)

Point estimate for population mean=sample mean=2.6000

b)

Population distribution should be normal.

c)sample standard deviation

df=13-1=12

critical t value=TINV(0.01,12)=3.0545

99% confidence interval for true mean length

=2.6000+/-3.0545*(0.339116/sqrt(13))

=2.6000+0.2873

=(2.3127, 2.8873)

d)Correct option is:

99% of all the confidence intervals found using this same sampling technique will contain the population mean time.

e)

No,2 does not fall within limits of above CI or as both limits are greater than 2.

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