Question

- LR LA A 8-1: The man shown is holding a rod of mass m and length LR initially in a horizontal position while rotating at a constant rate of as drawn. The man then gives the rod an additional constant known angular acceleration of a about the -be = -êg axis. For the analysis here assume that that the angular rate 12 remains constant. Determine: (a) the angular velocity and angular acceleration of the rod throughout the motion (b) the acceleration of the center of mass of the rod throughout the motion (c) the quantities from (a) and (b), and all torque and force reactions at the hands, at the initial instant t = 0 (when a is provided). B Extra hints: A is not an inertial point. Careful when computing B/N. Take the inertial derivative, use transport theorem. Assume the hands are capable of providing all possible torque and force reactions. The principal moment of inertia component along the axis aligned with a rod is assumed to be zero (but the other 2 components are not zero).

Answer 1

Giveno mass = m Length = LR (a) Angular velocity, D a is constant about -69 = - co axis shead = ra= otat =xt cê) Total angular velocity = r trx = rêr-xtêo * Angular acceleration =-x êo acceleration of centre of moss, a= ar t axt of Aras 1 = Le whêo the abs + 4 (-at)<brz as loudeleo + alebs + a''ha llore € Force, Fr=ma. bre permbayekéo + «tabs + otro la bin] Torque = $ xả E m (Leputies + Alq bg) * ( 4 * b) {": 6 x6r zo} 1 = n lạưu sin 0 + 4x4xông ra quyên - = my 2X2