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50 M=2.0kN.m 100 160 100 Fig. 3 Fig. 4 Prob. 3. For the unsymmetric cross section shown in Fig. 3, a moment M is applied at +

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2- z = SAY ZH 29 - A. (60-16,4/-) 1. 1 100 - = SDY4 [102] + 96x4x(52) + (60X4x2 SO X4+96x4 + coxy J = 41-837 mm 2 Sbxyx25 +Ayil (2142, -38.58) Y = 31:42 160X20X10 +120x20x60 160X20 +120X20 4.2 Ža 16-28-581, 51-42) - gz 31.42mm 5412 (160X20)x(100] +

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