Question

A pendulum is attached to the cart that has a mass of 3m and that is free to move along the horizontal direction. From the rest condition, when the lumped mass m of the pendulum makes a 0 angle with the vertical, the pendulum is released. 3m L m Compared to the case in which the cart is fixed (it cannot move), when 0=0°, the speed of the lumped mass at the tip of the pendulum would be smaller. (Vcartmoves < Vcartdoesnotmove) Select one: True False

Answer 1

Solution When cant doesn't move zm L 1- Larse 1 (1050) tom 7 Regelance linc Emorgy of mass (m) is conserved. E Eq=0 → ya uct-G.se L. v. 2 2 OSO 241 (1–650) Vogo 1272. (1-10) "Absolutte Velocity bob athen o=0". cart does move ST) -Yam 19 โต) Tx m Yes

Faxcom cm sorvation of momentum pornciple, Momentum when A= - Momentum when (3m) Wamt m @m) V+ m Vim system is selensed from rest = 0 (3m V + m Vm zvont Vm Vm 3 3m cam) o Vm Absolute velocity of bob of mass "m? at o=0 Tom - Absolute relocity of block of mass at --231 (1-60) î (%) Relative Velocity of m om m-3m 7 w.yt 3m. Jm-am + Tom V m-am - To Vm 3 → & Vm = Vins

VM Å 3 4 (Om-om) (- Vzgl(1-680 Pegl (1-660) Vm 27 128L (1 660) (1/6) Note that V bob when calt moves រ៉ុង less than Voob when cart is gied. True Since is moreasing angular acceleration ☆ utice @) also acts CW direction m Atan o B avod arad ta tam Ansuoti To the top and labo to the right

3 7 can be determined by Stelative motion since TA is known to and Vo to both common relative velocity analysis. since point D is links AB and CE, angala velocity of link CDE can be found by analysis method. V VDC tv? known direction directio is knoan is known Vc can be determined by comparing § and ŷ components VE can be detomned. > As no tragetmation about aceloration is given, it is impossible to deamine WCDE and S. QUE Option is cototect answelt.