18. For the reaction H2(g) + LaTeX: \frac{1}{2}1 2O2(g) --> H2O(l) LaTeX: \DeltaΔH = -286 kJ/mol...
18. For the reaction H2(g) + LaTeX: \frac{1}{2}1 2O2(g) --> H2O(l) LaTeX: \DeltaΔH = -286 kJ/mol Calculate the enthalpy change when 4.73 g of hydrogen gas is reacted with excess oxygen.
Homework Answers
Molar mass of H2 = 2.016 g/mol
mass(H2)= 4.73 g
use:
number of mol of H2,
n = mass of H2/molar mass of H2
=(4.73 g)/(2.016 g/mol)
= 2.346 mol
Since delta H is negative, heat is released
when 1 mol of H2 reacts, heat released = 286.0 KJ
So,
for 2.346 mol of H2, heat released = 2.346*286.0/1 KJ
= 671 KJ
Answer: -671 KJ
Add Answer to:
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