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2.24 The following reactions might be used to power rockets: (1) H2(g) + 2O2(g) = H2O(g)...
Use Hess's law and the following data CH4(g) + 2O2(g) → CO2(g) + 2 H2O(g) AH° = -802 kJ mol-1 CH4(8) + CO2(g) —> 2CO(g) + 2 H2(g) AFH° = +247 kJ mol-1 CH4(g) + H2O(g) –> CO(g) + 3H2(g) AFH° = +206 kJ mol-1 to determine A.Hº for the following reaction, an important source of hydrogen gas CH4(8) + +02(8) — CO(g) + 2 H2(8)
Given that H2(g) +F2(g) → 2HF(g) 2 H, (9) +0,(8) — 2H,O(1) calculate the value of AHin for A Hisn = -546.6 kJ mol- A Hixn = -571.6 kJ mol- 2F2(g) + 2 H,O(1) — 4 HF(g) + O2(g) AH = kJ.mol-1 KJ-mol-'
You are given the following data. AH = = -286.0 kJ H2(g) + 1/2O2(g) → H20(1) N2O5(9) + H20(1) → 2 HNO3(aq) 1/2 N2(9) + 3/2 02(9) + 1/2 H2(9) AH = -77.0 kJ HNO3(1) AH = -174.0 kJ Calculate the AH for the reaction given below. 2 N2(g) + 5 O2(g) → 2 N205(9) k] Need Help? Read It Supporting Materials Periodic Table E Constants & Factors Supplemental Data
CH_(g) + 2O2(g) → CO2(g)+ 2H2O(1) AH = -890.4 kJ When 1 mole of CO2(g) is produced, what is the enthalpy change? When 3 mol of O, is reacted with an excess of CH4, what is the enthalpy change? When 1 mole of H,O(l) is produced, what is the enthalpy change?
18. For the reaction H2(g) + LaTeX: \frac{1}{2}1 2O2(g) --> H2O(l) LaTeX: \DeltaΔH = -286 kJ/mol Calculate the enthalpy change when 4.73 g of hydrogen gas is reacted with excess oxygen.
6. Given H2(g) + 22 O2(g) → H2O(1), AH° = -286 kJ/mol, Determine the standard enthalpy change for the reaction 2H2O(l) → 2H2(g) + O2(g) (2 pt)
Which of the following statements is false concerning the reaction
of hydrogen gas and oxygen gas given below?
H2(g)+1/2O2(g)>H2O
Which of the following statements is false concerning the reaction of hydrogen gas and oxygen gas given below? H2(g) +029) - H20(1; AH = -285.8 kJ Select one: a. For the reaction H2(g) + O2(g) - H2O(g), AH is not equal to -285 b. If the equation is reversed, AH becomes +285.8 kJ. If the equation is multiplied by 2, AH...
2. Given the following data: H2O(l) → H2(g) + 1/2O2(g) ΔH° = 285.8 kJ 2HNO3(l) → N2O5(g) + H2O(l) ΔH° = 76.6 kJ 2N2(g) + 5O2(g) → 2N2O5(g) ΔH° = 28.4 kJ Calculate ΔH° for the reaction: 1/2N2(g) + 3/2O2(g) + 1/2H2(g) → HNO3(l) Note that you should be able to answer this one without needing to use any additional information from the thermo table. I've attempted this question multiple times. I am able to get to the simplified eqaution...
Gasoline (octane) burns according the following equation. 2 C3H18 (1) + 25 O2 (g) 16 CO2 (g) +18 H20 (1) AH°= - 10,943 kJ How much heat is released when 10 g of octane is burned? (The molar mass of C = 12.0 g/mol, the molar mass of H = 1.0 g/mol). 960 kJ 62,400 kJ 480 kJ 1920 kJ
Gasoline (octane) burns according the following equation. 2 C3H18 (1) + 25 O2 (g) 16 CO2 (g) +18 H20 (1) AH°= – 10,943 kJ How much heat is released when 10 g of octane is burned? (The molar mass of C = 12.0 g/mol, the molar mass of H = 1.0 g/mol). O 1920 kJ O 960 kJ 480 kJ 62,400 kJ