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Question 3 Question 3 - 6 pts Calculate the volume of 0.106 M NaOH needed to neutralize a 50.00 mL sample of 0.0950 M HNO 44.
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Answer #1

This can easily be solved by using normality equation as discussed N1V1=N2V2

O.106 × V = 0.0950 × 50.00

V = (0.0950×50.00)÷0.106

= 4.750 ÷ 0.106

= 44.811 ml

Therefore the first option is correct.

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