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-3.5A Problem 8: Consider the circuit in the diagram, with sources of emf listed below. Randomized Variables : 81 = 22 V IreV
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WW Vse loop i am & Hiom k am happy the from Kirchoffs law at point a 13 = I1 +12 from Kirchoffs law in loop 1 &1-1111 -1R5118.7512 + 78.2517 = 32.5 solving equation 118.7512 + 78.2511 = 32.5 40.512 – 25.111 = 24 12 = 0.438A 11 = – 0.249A Here nega

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