Question

The velocity profile of a steady-state flow (u = 0.001 kg/m .s) between two parallel plates is given by the following relation, u(a) = 6 4-0). oszsh My -10 mm Calculate the shear stress in Pa) acting on the a) at 2 = 0 b) at 210 mm

Answer 1

ut z)= 042-3) - Tallinn th ī (shear stress) ht edu dZ. Hz Viscosity = 0.001 kg hilo lomon ms clo (a). Z=0 delz=0 100g =0.01 m I (shear stress! (0.001) du du 6 - 122 h2 0-01 dz Z=0 h ł = 0.6 Pa = shear stress atz=0 I = 2:001) x 6 6 (6) 2 z=10mm a 12 z du dz /2=lo man du h 1 Oool h2 Z=10mm 12 (0.01) - 6 (0.01) 0.01 6 Oool 2 dz

T(2= 10 mm) = M du M dz/zzlama Il =-0.6 Pa 1/2=lomma 0.001 X-6 0.01 Рас -0.6

Please note

h = 10 mm = 0.01 m

We have to put all values OF VARIABLES ( HEIGHT, VISCOSCITY) in SI UNITS TO GET ANSWER IN PASCAL.

HEIGHT h = 10 mm = 0.01 m

(A)

Shear stress at z = 0

Shear stress = 0.6 pa

(B)

Shaer stress at z = 10 mm = 0.01 m

Shear stress = - 0.6 pa

Negative sign shows Direction of shear stress opposite to flow direction.

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