Question

9 points each blank, 6 points total] Determine the equivalent values of capacitance and inductance at the of the component configurations below. Assume no mutual inductance effects with the inductor circuits. 5uF 15uF 10uF 10uF 5uF Equivalent capacitance Equivalent capacitance Equivalent capacitance 15uH 10uH 30uH Equivalent inductance Equivalent inductance Equivalent inductance

Answer 1

C_eq = C_1 C_2/C_1 + C_2 C_eq = C_1 + C_2 L_eq = L_1 + L_2 implies L_eq = L_1 + L_2/L_1 + L_2 \r\n Equivalent capacitance C_eq = 5 times 5/5 + 5 = 25/10 mu F C_eq = 2.5 mu F C_eq = (5 + 15) mu F C_eq = 20 mu F C_eq = 20 times 20/40 C_eq = 10 mu F \r\n Equivalent inductance L_eq = 10 + 30 L_eq = 40 mu H L_eq = 10 mu H times 10 mu H/(10 + 10) mu H L_eq = 10 times 10 mu F/20 L_eq = 5 mu F 30 parallel to 30 = 15 mu H L_eq = 15 mu H + 15 mu H L_eq = 30 mu H