Question

Problem 10.33 Complete the following table for an ideal gas: P V n T 2.10 atm 1.20 L 0.520 mol ? K 0.320 atm 0.270 L ? mol 32 ∘C 660 torr ? L 0.335 mol 370 K ? atm 595 mL 0.270 mol 280 K

Part A Complete the first row of the table. T = 59.1   K   SubmitMy AnswersGive Up Correct Significant Figures Feedback: Your answer 59.02 K was either rounded differently or used a different number of significant figures than required for this part. Part B Complete the second row of the table. n = .0027   mol   SubmitMy AnswersGive Up Incorrect; Try Again; 5 attempts remaining Part C Complete the third row of the table. V = .1878   L   SubmitMy AnswersGive Up Incorrect; Try Again; 5 attempts remaining Part D Complete the fourth row of the table. P = 78.7   atm   SubmitMy AnswersGive Up Incorrect; Try Again; 5 attempts remaining

Answer 1

A)

Given:

P = 2.1 atm

V = 1.2 L

n = 0.520 mol

use:

P * V = n*R*T

2.1 atm * 1.2 L = 0.52 mol* 0.0821 atm.L/mol.K * T

T = 59.0 K

B)

Given:

P = 0.32 atm

V = 0.27 L

T = 32.0 oC

= (32.0+273) K

= 305 K

find number of moles using:

P * V = n*R*T

0.32 atm * 0.27 L = n * 0.08206 atm.L/mol.K * 305 K

n = 3.45*10^-3 mol

= 0.00345 mol

C)

Given:

P = 660.0 torr

= (660.0/760) atm

= 0.868421 atm

n = 0.335 mol

T = 370.0 K

use:

P * V = n*R*T

0.868421 atm * V = 0.335 mol* 0.0821 atm.L/mol.K * 370 K

V = 11.7 L

D)

Given:

V = 595.0 mL

= (595.0/1000) L

= 0.595 L

n = 0.270 mol

T = 280.0 K

use:

P * V = n*R*T

P * 0.595 L = 0.27 mol* 0.0821 atm.L/mol.K * 280 K

P = 10.4 atm

Answer: 10.4 atm