Question

The two plates are a distance D apart. The surface area of the face of each plate is A, the total charge on each plate is +Q and ?Q, and the resulting uniform charge density is +?0 and ??0 respectively so that ?0=Q/A.

×4 1 3 ×2 ×1

Use the principle of superposition to identify the correct statement(s) about the electric field at points 1,2,3, and 4.

The field at points 1 and 4 will be zero because the fields from positively and negatively plates will cancel each other

The charge on positively charged plate will not contribute to the field at point 1 because there's metal between them

The charge on negatively charged plate will not contribute to the field at point 4 because there's metal between them

The fields at points 1 and 4 will be the same magnitude as from a single plate but in opposite directions

The field at points 2 and 3 will be the same and the magnitude of the field is twice that of the field from a single plate

The field at points 2 and 3 will be zero because the fields from negatively and positively charged plates cancel each other

Calculate the electric field at points 1,2,3, and 4 in terms of electric charge density ?0 on each plate and ?0. Assume the positive direction if from right to left.

What is the potential difference, V0, between the plates

0 0
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Answer #1

The electric field strength due charge plates is, 0 2 3 4 The test charge is always positive. Like charges repels each other

The total electric field strength on point 1 is, 280 280 The point 3 moves left side due to repulsive force from plate B and

4) The fields at points 1 and 4 (E-0) will not be same magnitude as from a single plate 2e ANS: False 2 and 3(EL) will not be

The potential difference at point 1 is, The potential difference at point 2 is, deo The potential difference at point 3 is, d

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