Question

Q4) Find the interal normal force, shear force and bending moment at point is located at distance 3ft from left side (20 points) Draw your section here 300 lb 200 lb/ Equation for finding normal force, N. Normal force, N Тb Equation for finding shear force, V. shear force, Ve Тb Equation for finding bending moment, M. Bending moment, M= ПЬНt

Answer 1

Section (Free body) X Wn 2001b/ft 300 lb 21 مال A 3 ft B. B Eqh for Normal Force 6 ft At any section x- at a distant of a ift from VG) VA300 -- *2200 -0 VA -300-100X - O VA - 300+100x7 Art Normal Force VA-N = 300 + 100 X but a=6ft VA = 300+100x6 = 900N And Equation for fincling Shear Force Let toad ration at x-x, at a distance of a ft from B, be wn' on similar. A Bxxland ABAA! Xx! Bx' AAC BA AA'= 200 kbist Bx'- x, BA= 6ft wa 200 6 Wn= 1002 2007 - 6 3 so SCW 3-300 - مهارات الا Šta =foo - 502') -Źxx x 10021 And

Shear Force Calculations Shear Force at B, X=0 SB=-300 - Sox 1072 =-300 lb -sox (87² So 3 Shear force at A , x=oft SA --300 3 --300 - 50 x 36 = -300-600=-qoolb 3 So, Maximum Sheau Foru Smax =-gooeb / And Equation for finding bending moment (m) m(a)=-800x-Ź xax looy M (a) =-303 - Son And some and Moment Calculations moment at B, MB M (3) -3000 sox03 o lbft Moment at A, MA, x= 6ft MCA) = -300x6 x63--3000lbft 3 50 X 9 Moment cit c. MC 2= 3ft. 50x33 -1050 lbft MCS -300 X3 - 9 Mc =-1050 lhtt] Ar

Normal Forceat point c. 7 = 3ft Nc = 100x3 3 lou eb/ft Ang (Wn= 1000/3) Shear force at point C:, *=3ft Sc =-300-50x3? Gotha Sc 300-150 .450 lb (Sca An