How much energy is required to heat 36.0 g H_2O from a liquid at 65degree C...
How much energy is required to heat 36.0 g H2O from a liquid at 65°C to a gas at 115°C? The following physical data may be useful. ΔHvap = 40.7 kJ/mol Cliq = 4.18 J/g°/sup>C Cgas = 2.01 J/g°/sup>C Csol = 2.09 J/g°/sup>C Tmelting = 0°/sup>C Tboiling = 100°/sup>C
How much energy is required to heat 36.0 g H2O from a liquid at 55.0°C to a gas at 150.0°C? The following physical data may be useful. Molar Mass(H2O) = 18.0 g/mol ΔHvap = 40.7 kJ/mol Cs;liquid = 4.18 J/g oC Cs;gas = 2.01 J/goC Tb(H2O) = 100.0 oC
How much energy is required to heat 87.1 g acetone (molar mass=58.08 g/mol) from a solid at -154.0°C to a liquid at -42.0°C? The following physical data may be useful. ΔHfus = 7.27 kJ/mol Cliq = 2.16 J/g°C Cgas = 1.29 J/g°C Csol = 1.65 J/g°C Tmelting = -95.0°C
How much energy (heat) is required to convert 52.0 g of ice at -10.0 C to steam at 100 C?Specific heat of ice: 2.09 J/g * C DHfus = 6.02 kJ/molSpecific heat of water: 4.18 J/g * C DHvap = 40.7 kJ/molSpecific heat of steam: 1.84 J/g * C
HOw much energy is required to heat 36.0g H2O from a liquid at 65C to a gas at 115C? The following physical data may be uselful.Hvap=40.7kJ/molC liquid=4.18C gas=2.01C solid= 2.09T melting=0 CT boiling=100 CThe answers about 87.7 kJ However I'm not sure how you get this,so H=H heating liquid+H vap+H heating gas. I'm not getting the same answer
Calculate the amount of heat (in kJ) required to raise the temperature of 14.0 g of liquid H_2O (molar mass = 18.0 g/mol) from 25.0 degree C to the boiling point and then to vaporize the liquid at that temperature, (specific heal capacities: H_2O(s): 2.06 J/g degree C, H_2O(l): 4.18 J/g degree C, H_2O(g): 1.92 J/g degree C; heat of fusion of H_2O: 6.02 kJ/mol; heat of vaporization of H_2O: 40.7 kJ/mol; melting point of H_2O: 0.0 degree C, boiling...
Methane, CH_4, is a gas room temperature but dichloromethane, CH_2Cl_2 is a liquid. Why? Water will rise up into a capillary tube. Why, and how is this phenomenon important in nature? Calculate the amount of heat in kJ that is required to heat 20.0g of ice from -25 degree C to 90 degree C, and sketch a heating curve for the process. The specific heat of ice is 2.11 J/(g, degree C); water 4.18 J/(g, degree C) and the Delta...
Using the provided data, calculate the amount of heat, in kJ, required to warm 21.7 g of solid water, initially at -10. °C, to gaseous water at 112. °C. water molar mass 18.0153 g/mol melting point 0. °C boiling point 100. °C ΔHfus 6.02 kJ/mol ΔHvap at bp 40.7 kJ/mol Cs, solid 2.09 J/g⋅°C Cs, liquid 4.18 J/g⋅°C Cs, gas 1.87 J/g⋅°C 72.4 kJ 57.6 kJ 58.5 kJ 66.3 kJ 13.9 kJ
What quantity of energy does it take to convert 1.29 kg of ice at -23 degree C to water at 35 degree C? Specific heat capacities: ice 2.03 J/(g degree C) and liquid water 4.184 J/(g degree C) Delta H_vap = 40.7 kJ/mol; Delta H_fus = 6.02 kJ/mol A) 680 kJ B) 257 kJ C) 6.04 times 10^4 kJ D) 3.59 times 10^3 kJ
You have a 10.0 g sample of water at 373 K. How much energy must you use to turn this into steam? AHvap = 40.7 kJ/mol AHfus = 6.02 kJ/mol Cliq - 4.184 J/g °C Cgas = 2.01 J/gºC Csol - 2.09 J/g°C Tmelting = 273.0 K Tboiling = 373.0 K 45346 3472.72 J 22598.63 -4534.6