Question

-00= dil H,O (d) HCECH NaHCH.CHEO ether in H,90 (H,180 has isotopically labelled O) 2 equiv NBS heat CHO O CH,CH, MgBrdil. H,

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Answer #1

In the first step Grignard reagent is formed. As in the reactant the halide atom (Bromine) is more electronegative than carbon atom so bromine has negative charge and carbon atom has positive charge. After the reaction with magnesium, in the presence of ether (solvent), the magnesium atom comes between the carbon atom and bromine atom. And now the carbon atom becomes negatively charged because carbon is more electronegative than magnesium.

ether

In the second step, the Grignard reagent attack on the epoxide. The carbon atom of Grignard reagent is negatively charged and it is nucleophilic (electron rich) in nature. In epoxide the oxygen is more electronegative so the Grignard reagent attacks on the carbon atom (electron deficient) adjacent to oxygen atom in epoxide.

ما د عمر

In the third step, O- abstracts one of the proton from the H3O+

So the final answer is written below

ܒܶS 19 ether Jail Hot

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