Question

AEC-357 SITE ENGINEERING NAME: I H.I. F.S. B.S. 4.61 3.01 STA BM #6 HYD #1 STA #1 BM #4 STA #6 BM #6 ELEV. | ELEV. DESCRITION

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Answer #1

B.S = Back sight

F S =fore sight

H I =Height of instrument

Height of instrument = Elevation /reduced level + BS

Elevation/reduced level = HI-FS

Station B.S I.S. F.S. H.I. ELEVATION
BM #1 4.61 891.43+4.61
=896.04

891.43

HYD #1 3.01 9.11 886.93+3.01
=889.94

896.04-9.11
=886.93

STA #1 -4.03 889.94

889.94+4.03
=893.97

BM #4 3.66 6.73 883.21+3.66
=886.87

889.94-6.73
=883.21

STA #6 14.91 5.45 881.42+14.91
=896.33

886.87-5.45
=881.42

BM #6 4.91 896.33

896.33-4.91
=891.42

26.19 26.20

STA #1 is inverted reading.so it is taken as -4.03.

check

for check,\sumBS , \sum FS should be positive.

\sumBS=26.19

\sumFS=26.20 (sum of positive F.S.)

\sumFS - \sum BS =First elevation - Last elevation

\sumFS - \sum BS = 26.20-26.19 =0.01

First elevation - Last elevation =891.43 - 891.42 = 0.01

so \sum FS - \sum BS =First elevation - Last elevation

The calculation is correct

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