Question

Question 4- E1 (6 marks) 4.1) (3 marks) Use the voltage division principle to calculate v in the figure below R, 202 10 V R 202 4.2) (3 marks) What values of power are absorbed by each resistor, Pai, Paz and Pr? PRI- PR2 PR3

ans,

4.1	v = 3.33 V
4.2	P_R1 = 2.22 W, P_R2 = 0.556 W, P_R3 = 0.556 W

Answer 1

Given circuit is Now R_2 and R_3 are in parallel, so reducing the circuit, we can place a single resistor which is equivalent to these two parallel resistors R = R_2 times R_3/R_2 + R_3 = 20 times 20/20 + 20 = 400/4 R = 10 sim Now, the circuit will be By using voltage division principle we can calculate the voltage v v = 10 times 10/20 + 10 v = 100/30 v v = 3.33 v The lane voltage will be there across The two 20 Ohm resistors because they are in parallel. (4.2) power absorbed by the resistor we know that for a resistor given below rightarrow using above equations we can find power i_1 10 - 3.33/20 = 0.333 rightarrow Power absorbed by resistor R_1 is P_R_1 = i_1^R_1 = (0.333)^(20 Ohm) P_R_1 = 2.22 w \r\n rightarrow power absorbed by resistor R_2 is P_R_2 = v^2/T_2 = (3.33)^2/20 P_R_2 = 0.556 w