A container of gas has a volume of 6.20 L at 2.8 atm. What is the...

Question

Question

A container of gas has a volume of 6.20 L at 2.8 atm. What is the original volume if the pressure was initially 5.6 atm?

Answer 1

Answer #1

From

P1*V1=P2*V2...........................(1)

we have P1=5.2 atm,V1=?

P2=2.8 atm V2=6.20 then

and using the equation 1 we get

V1=3.1 L

These calculations are done using Temperature is constant throughout as there is no mention for temperature.

Answer 2

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