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hr at is the aceeferation in m eg Aw airplav es that starts Hom rest, reachesooo miks what is the accelerahoN ?? the airphw? if t takes the Airpawe ihr Aom city to city veloeity is6Lid the dstsce in sscconds. 5e9

Answer 1

Data (u) = [80 km/hr] (v) = [100km/hr] (t) = (6sec) (a) = ? Sol: By kinematics, we have (v) = (u + at) rightarrow (i) [where (u) = (initial velocity) (v) = (final velocity) (a) = (acceleration) (t) = (time taken)] Here, (t) = (6 sec) (u) = [80 km/hr] = [80 times 5/18] = [22.22m/sec] [((x(km/hr))times 5/18) = [x(m/s)]] (v) = [100 times 5/18] = [27.77 m/sec] (a) = ?\r\ntherefore (i) rightwardsdoublearrow (a) = [v � u/t] = [(27.77 � 22.22/6)m/s^2)] = [0.925 m/s^2] rightwardsdoublearrow (a) = [0.925 m/s^2] is acceleration of car. 2) sol: Data (u) = 0(because Starts from rest) (v) = [1000 miles/hr] (a) = ? a) (t) = (1 hr)\r\nHere, (t) = (1 hr) = (3600 sec) [because (1 hr) = (3600 sec)] (u) = (0) (v) = [[1000 times 1609.34/3600]m/sec] [because (1 mile) = (1609.34 m) & (1 hr) = (3600 sec)] tripleequalto [447.04 m/sec] (a) = ? therefore (i) rightwardsdoublearrow (a) = (v � u/t) = [[447.04 � 0/3600]m/s^2] = [0.124 m/s^2]