As we see from the illustration, physical address 1650 lies in the segment that resides at addresses 1504 - 1791 in memory.
Note that 1504 is the base-address of this segment, and 1791 is the end-address of this segment.
As seen from the illustration, the segment between 1504 - 1791 has segment-number 4.
Also, the segment-offset for 1650 is given by
= (physical address) - (base address of segment)
= 1650 - 1504
= 146
So the answer is
(4,146)
4. PURE SEGMENTATION QUESTION (check the illustration provided) What is the logical address for the following...
A 16 bit logical address is split into 5 bit page number and 11 bit page offset. Answer the following questions in the space provided: a) The page size is ____ bytes b) The page table size is ____ c) if the page table is as shown below, then the corresponding physical address for 0x174F is given by: ____. Question 29 (3 points) Saved A 16 bit logical address is split into 5 bit page number and 11 bit page...
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USE THIS ILLUSTRATION BELOW FOR DYNAMIC PARTITIONING QUESTIONS Hole 4 Hole 1 20K Hole 2 12K Hole 3 10K Hole 5 40K Hole 6 15K Hole 7 18K Hole 8 14K 22K Request 1 24K Request Request Request 2 3 4 10K 14K 18K DYNAMIC PARTITIONING SCHEME QUESTION (check the illustration provided) Which hole is taken for each successive segment request if we use BEST FIT algorithm. Use this format for the answer: request # - hole #. Sample answer:...
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