Question

switch (n % 10) case 1: x = n; break: case 3: - y = 10; case 5: x-n.2: break; default: x=0; y = 0; break; ] What will be values of x and y equal to after exiting this switch operator if right before the switch, values of and y were both equal to -35, and n was one of these: n before switch xafter switch y after switch 21 12 15 25 17 173

please answer in C code and leave comments on what the code does in the code

Answer 1

Answer:

In before switch x after switch y after switch 21 21 -35 12 o 0 30 15 -35 25 50 -35 21%10 = 1. Will go to case 1. x =n so, x = 21 and y = -35 (same as initializatioin) 12%10 = 2. We don't have any condition with case 2. So, It goes to default then x = 0, y = 0 15%10 = 5. Will go to case 5. x = n*2 so, x = 30 and y=-35 (initialed value) 25%10 = 5. Will go to case 5. x= n*2 so, x = 50 and y = -35 (initialed value) 17%10 = 7. We don't have any condition with case 7. So, it goes to default then x = 0, y = 0 173%10 = 3. Will go to case 3. x= n so, x = 173, y = 10. Since there is no break statement for this case. It continues to go to next case that is case 5 where x= n*2 so, x = 173*2 => x= 346 and y = 10 0 0 17 346 10 173

Program:

#include <stdio.h>

int main()
{
    // Initializing x,y values to -35
    int x = -35, y = -35;
    // Initializing n value to 173.
    // Note: Change this n value as per given values to get x,y values
    int n = 173;
    // switch condition takes the remainder when n is divided by 10
    switch(n%10) {
        // If remainder is 1
        case 1: x = n;
            break;
        // If remainder is 3
        case 3: x = n;
            y = 10;
        // If remainder is 5
        case 5: x = n*2;
            break;
        // If remainder doesn't match to any above cases then it comes into this
        default: x = 0;
            y = 0;
            break;
    }
    // Printing the x and y values
    printf("x = %d\ny = %d", x, y);

    return 0;
}

Output: For n = 173