If you have any doubt please make a comment. Thank you
n=91 please help asap Core depth 5cm Problem 2 [15] Given the balanced three phase system...
A balanced 3 phase system is given with the following specifications: - The balanced system has a single delta-connected source and a single Y-connected load side. - Between the source and the load side there is the line_impedance = Rlinr+ jXline. - The average power and reactive power delivered form the source is Pin = 500 Watt and Qin = 500 VAR respectively. - The source side line voltage is Vline_source=100 Volt (rms). - The load side average and reactive...
zzoom in if image is not clear Part A In a balanced three-phase system, the source is a balanced Y with an abc phase sequence and a line voltage Vab = 215Z 55°V. The load is a balanced Y in parallel with a balanced A. The phase impedance of the Y is 5+3j 12/0 and the phase impedance of the A is 3-9 12/0. The line impedance is 1.4+0.83 12/9. Use the single phase equivalent circuit to calculate the line...
A balanced Y-connected load with a phase impedance of 10 + j 4 Ω is supplied by a balanced, positive sequence Δ-connected voltage source having Vab 208∠0o V. Given that the line impedance is 0.8 + j 0.3 Ω per phase. (i) Construct a single-phase equivalent circuit of the three-phase system. (ii) Calculate the phase currents of the load. (iii) Calculate the line voltages at the load.
connected 3-phase load consisting of three identical impedances Z= 48ے36.870 W. 3-Phase System Using MATLAB/Simulink Analysis of Y-Y connected balanced 3-phase circuit using Matlab A 2400-V rms balanced 3-phase 60-Hz supply is applied to a balanced Y-connected 3-phase load consisting of three identical impedances Z- 4836.870 W. The circuit diagram is shown in Fig. 3. Taking the phase to neutral voltage Van as reference. Calculate 1) The phase &line voltage Van, Vab 2) The phase current for any phase- line...
Review | Constants Part A An ach sequence balanced three-phase Y connected source supplies power to a balanced three-phase A-connected load with an impedance of 12 + j6 / 6. The source voltage in the b-phase is 2302-50 V. The line impedance is 1+j / Use the single-phase equivalent circuit for the a-phase to find the current in the a-phase of the load Express your answer in amperes to three significant figures. Enter your answer using angle notation. Express argument...
Problem 1 A balanced three-phase source supplies two loads, as shown in Fig. 1. The voltage rating of the 3-phase source is 6600230° V. Load 1 impedance is 2 =45.9+j572 per phase, Load 2 impedance is Zz=12+j252 per phase. The loads are connected to the source by a 3-phase line with the impedance of ZLine=2.7+j52 per phase. Zine Load 1 a Load 2 a la Z Z Z2 VL Zino Z2 b с 22 с Zine b Fig. 1 Balanced...
7. A balanced three-phase Y-connected generator with positive sequence has an impedance of 0.2+ 20.5 216 and an internal voltage of 220 V/6. The generator feeds a balanced three-phase Y-connected load having an impedance of 39 + j28 /6. The impedance of the line connecting the generator to the load is 0.8 +j1.5 /6. The a-phase internal voltage of the generator is specified as the reference phasor. (a) Construct the a-phase equivalent circuit of the system. (5 points) (b) Calculate...
Question 31 (17 points) 120/120 single-phase transformer. Calculate the values for the equivalent circuit for the single-phase transformer for the given short and open circuit test shown below. (2 points) Draw the equivalent circuit. (1 point each) Find Ssc, QSC, Soc, Qoc, R1, R2, XI, X2, Rc, Xm, PFsc, PFoc, (esc θ。c) phase angel between V and I. What is the power rating of this transformer? Short circuit test (performed at High Voltage side) Vsc 16.20V rms, Isc 5.00 A...
Please show all work Problem #2 For the three-phase balanced system shown in the figure determine the following: 1. V and I 2. The three-phase power absorbed by the load. 3. The real and reactive three-phase powers lost in the transmission line. Р 4. The power efficiency, N =- -Load *100. of the three-phase system. Source V = 100 20° V. a 112 j122 A + ommo 15+ j2102 D=1002-120V.. 12 122 B 15+j2102 15+ j2 152 D =100420 V...
Learning Goal: To find voltages and power in a balanced three-phase circuit. Three identical AC voltage sources, each with amplitude 170 V, are connected in a Y configuration to three identical resistances, each 50 , also in a Y configuration. There is also a fourth, neutral line in the circuit (see diagram). The voltage sources are each 120° out of phase from the other two sources R RE R - Part A - Load current What is the RMS current...