Solution:- This problem is based on the equation, q = m c delta T
where q is the heat energy, m is mass in grams, c is specific heat capacity in J/(g. 0C) and delta T is change in temperature that is, final temperature - initial temperature.
specific heat capacity, c for gold is 0.129 J/(g. 0C). mass is given as 3.5 kg = 3500 g
delta T = 67 - 21 = 46 0C
let's plug in the values in the formula....
q = 3500 g x 0.129 J/(g. 0C) x 46 0C
q = 20769 J
so, the amount of heat required would be 20769 J that could also be round to 21000 J (two sig figs) and could also be written as 21 kJ.
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