(a) The population proportion = 150 / 450 = 0.333
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(b) The Z critical (2 tail) for = 0.02, is 2.326
The Confidence Interval is given by , where
The Lower Limit = 0.333 - 0.052 = 0.281
The Upper Limit = 0.333 + 0.052 = 0.385
The 95% Confidence Interval is 0.281 and 0.385
Independent random samples were taken of male and female members of University Entrepreneurship Club. These members...
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The information below is based on independent random samples taken from two normally distributed populations having equal variances. Based on the sample information, determine the 98% confidence interval estimate for the difference between the two population means. n = 12 X1 = 57 S1 = 9 n2 = 11 X2 = 54 S2 = 8 The 98% confidence interval is $(11-12) (Round to two decimal places as needed.)
please answer as soon as possible Consider the following results for two independent random samples taken from two populations. Sample 1 Sample 2 1 13.2 11.3 σί 2.1 σ2-3 What is the point estimate of the difference between the two population means? (to 1 decimal) 2 Provide a 90% confidence interval for the difference between the two population means (to 2 decimals) 98 3.02 Provide a 95% confidence interval for the difference between the two population means (to 2 decimals)....
QUESTION 1 Salary information regarding two independent random samples of male and female employees of a large company is shown below. Male Female 36 41 72 Sample size 64 Sample mean salary (in44 S1000s) Population variance 128 The point estimate of the difference between the means of the two populations (Male - Female) is -28 4 -4 Refer to Question 1. The standard error for the difference between the two means is_ 4 7.46 4.24 2.0 Refer to Question 1...
Consider the following results for independent samples taken from two populations. Sample 1 Sample 2 n1 = 500 n2 = 200 p1 = 0.47 p2 = 0.33 a. What is the point estimate of the difference between the two population proportions (to 2 decimals)? b. Develop a 90% confidence interval for the difference between the two population proportions (to 4 decimals). to c. Develop a 95% confidence interval for the difference between the two population proportions (to 4 decimals). to
Unit-4-Exam-Part-2: Problem 2 Prev Up Next (2 pts) Random samples of female and male UVA undergraduates are asked to estimate the number of alcoholic drinks that a typical weekend. The data is below Females (Population 1):1,2, 4, 3, 4,3, 0, 4, 3,0 Males (Population 2): 7, 7,7,7,5, 6, 7,7,4, 4 Give a 93.6% confidence interval for the difference between mean female and male drink consumption. variances are equal.) on Confidence Interval
Consider the following results for independent samples taken from two populations. Sample 1 Sample2 2 200 P2 0.31 P1 0.48 a. What is the point estimate of the difference between the two population proportions (to 2 decimals)? b. Develop a 90% confidence interval for the difference between the two population proportions (to 4 decimals. Usez-table. c. Develop a 95% confidence interval for the difference between the two population proportions (to 4 decimals. Use z-table. to to
Consider the following results for independent samples taken from two populations. Sample 1 Sample2 n2 200 P2# 0.31 P1- 0.43 a. What is the point estimate of the difference between the two population proportions (to 2 decimals)? | b. Develop a 90% confidence interval for the difference between the two population proportions (to 4 decimals). Use z-table. to c. Develop a 95% confidence interval for the difference between the two population proportions (to 4 decimals). Use z-table. to
onsider the following results for independent samples taken from two populations. Sample 1 Sample 2 n1 = 500 n2= 300 p1= 0.48 p2= 0.31 a. What is the point estimate of the difference between the two population proportions (to 2 decimals)? b. Develop a 90% confidence interval for the difference between the two population proportions (to 4 decimals). Use z-table. to c. Develop a 95% confidence interval for the difference between the two population proportions (to 4 decimals). Use z-table....
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