What is the change in internal energy of a system if the system (i) absorbs 58 J of heat and does 58 J of work? (ii) absorbs 125 J of heat and does 687 J of work? (iii) evolves 280 cal of heat and has 1.25 kJ of work done on it?
(i) absorbs 58 J of heat. So, Q = +58 J
does 58 J of work. So, W = -58 J
use:
delta U = Q + W
= 58 J - 58 J
= 0
Answer: 0
(ii) absorbs 125 J of heat. So, Q = +125 J
does 687 J of work. So, W = -687 J
use:
delta U = Q + W
= 125 J - 687 J
= -562 J
Answer: -562 J
(iii) evolves 280 cal of heat.
So, Q = -280 cal
= -280*4.184 J
= -1171.52 J
= -1.17 KJ
has 1.25 kJ of work done on it.So, W = +1.25 KJ
use:
delta U = Q + W
= -1.17 KJ +1.25 KJ
= -0.08 KJ
Answer: -0.08 KJ
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