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An ideal gas is brought through an isothermal comp

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Answer #1

W = work done = Q = energy released = - 7820 J

V1 = initial volume = 268.2 x 10-6

V2 = final volume = 139.7 x 10-6

T = temperature

work done is given as

W = n RT ln(V2/V1)

- 7820 = 5 (8.314) T ln(139.7 x 10-6 / (268.2 x 10-6))

T = 288.42 K

using the formula

PV1 = n RT

P (268.2 x 10-6) = 5 x 8.314 x 288.42

P = 4.5 x 107 Pa

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