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l put kinetic energy of 1 equal to kinetic energy of 2. and it didnt work any ideas? KA08: Ch 25 Problem 29.3 2 of 7 inl302]:- .5*1.67 * 10 ^-27 * 46 ??? A 2 outo2- 1.76686 x 10-18 ni3os)- Solve [1.76686-18 A proton is released from rest at the positive plate of a parallel-plate capacitor. It crosses the capacitor and reaches the negative plate with a speed of 4.60x104 m/s Part A 59.1 10 A -31VA2, V] v1.97859 x10°), [v-»1.97059x 10°)) What will be the protons final speed if the experiment is repeated with double the amount of charge on each capacitor plate? ?? .97 106 m/s Submit Previous Answers Request Answer X Incorrect: Try Again: 3 attempts remaining

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Answer #1

The change in potential energy of the proton is, Ed The change in kinetic energy of the proton is, AK-K, -K, mv mv

From law of conservation of energy we have, - my v22gEd f m Whenthe amount ofcharge oncachplate isdoubled, thenthefinalvel Ci

Dividingboth the equations we have, NE For a parallel plate the electric field between the plates is given by, So the above e

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