Question

What is the molarity of a solution containing 88 8 grams of solute in 1366 7 mL of solution? mass of solute s 57 gmo) lar Select one a 3700 b 1.14 c 0.470 d 0.00114
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Answer #1

Ans. Moles of solute = Mass/ Molar mass

                                    = 88.8 g / (57 g/mol)

                                    = 1.5579 mol

Volume of solution = 1366.7 mL = 1.3667 L                    ; [1 L = 1000 mL]

Now, molarity = Moles of solute / Volume of solution in liters

                                    = 1.5579 mol / 1.3667 L

                                    = 1.139 mol/ L

                                    = 1.139 M = 1.14 M                                               ; [1 M = 1 mol/ L]

Thus, correct option is – b. 1.14 M

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