Question

What is the molarity of a solution containing 88 8 grams of solute in 1366 7 mL of solution? (molar mass of solute s = 57 g/mol)) Select one 3700 1.14 0.470 0.00114

Answer 1

Ans. Moles of solute = Mass/ Molar mass

                                    = 88.8 g / (57 g/mol)

                                    = 1.5579 mol

Volume of solution = 1366.7 mL = 1.3667 L                    ; [1 L = 1000 mL]

Now, molarity = Moles of solute / Volume of solution in liters

                                    = 1.5579 mol / 1.3667 L

                                    = 1.139 mol/ L

                                    = 1.139 M = 1.14 M                                               ; [1 M = 1 mol/ L]

Thus, correct option is – b. 1.14 M