SOLUTION :
Heat absorbed = m s (t2 - t1)
=> 125 = 25 * s * 2.7
=> s = 125 / (25 * 2.7) = 1.85 J / ( g ºC)
Specific heat of alcohol is = 1.85 J / (g º C) (ANSWER)
When a sample of alcohol absorbed 125 J of heat, its temperature rose from 0.0°C to...
3. Calculate the heat absorbed by 25.0 g of water needed to raise its temperature from 20.0°C to 65.0'C. The specific heat of water is 4.18 J/gºC. Show your work Final Answer 4. Aluminum metal has a specific heat of 0.901 J/g C. How much heat is transferred to a 6.75 g piece of aluminum initially at room temperature, 20.0°C, when it is placed into boiling water? The temperature of boiling water is 100°C. Show your work Final Answer 5....
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Calculate the heat absorbed by 25.0 g of water needed to raise its temperature from 20.0 to 65.0 degrees C. The specific heat of water is 4.18 J/gC
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