Question

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For a random sample of n = 124 U.S. cities the mean growing season length was x = 190.7 days. The population standard deviation is o = 42.8 days. Assuming the variable is normally distributed, find the 98% confidence interval (including units) of the population mean. State the distribution used. Give all digits provided by the calculator for the confidence interval. <p>Distribution used:</p> <p>Confidence interval:</p>

Answer 1

I Given that n=124 , x=190.it, o=42.8, d = 0.02. * using student's normal distribution (Z-dest) - * to find a.I we have formula x + Zolo in at 2:0.00 1.0.0 (too tailed) tal-2.326 - from 190.7 & (2:326) | vizu ) 190.7 + 8.9401 (181.9599, 199.6401) .: 98%...I [1810 7599 a l< 199.6401 * Given that no 8, x=9.64, S=1.7, 2:0.05 * osing studend it distribution Coldest) * To find it we have formula xt dahints at 2:0.05 lois , df = f, f.cv=2.365 from 9.64 4 (2:365) - 9.64 & 1.4215 8.2185, 11.0615 .: 95%.c.I 18.22 < l< (11.06