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State whether the following statement is True or False. The area under the standard normal distribution...
need help with the problems listed below For a random sample of n = 124 U.S....
need help with the problems listed below
For a random sample of n = 124 U.S. cities the mean growing season length was x = 190.7 days. The population standard deviation is o = 42.8 days. Assuming the variable is normally distributed, find the 98% confidence interval (including units) of the population mean. State the distribution used. Give all digits provided by the calculator for the confidence interval. <p>Distribution used:</p> <p>Confidence interval:</p> For a sample of n = 8 randomly...
Question 6 (6 points) The average weight of n = 32 randomly selected pickup trucks was...
Question 6 (6 points) The average weight of n = 32 randomly selected pickup trucks was x = 7230 pounds. The population standard deviation was o = 347 pounds. Assuming the variable is normally distributed, find the 94% confidence interval (including units) of the population mean. State the distribution used. Give all digits provided by the calculator for the confidence interval. <p> Distribution used:</p> <p>Confidence interval:</p> Question 7 (6 points)
i need a clear understand how to work out the problems below. Finding thevMean, Standard deviation,...
i need a clear understand how to work out the problems below.
Finding thevMean, Standard deviation, and confidence interval
The recorded high temperatures (in degrees Fahrenheit) in June for a sample of 17 US cities are listed below. Assuming the temperatures are normally distributed, find the 92% confidence interval (including units) of the population mean. Give the distribution used and the mean and standard deviation of the sample rounded to the nearest hundredth (two decimal places). Give all digits provided...
Use the standard normal distribution or the t-distribution to construct the indicated confidence interval for the...
Use the standard normal distribution or the t-distribution to construct the indicated confidence interval for the population mean of each data set. Justify your decision. If neither distribution can be used, explain why. Interpret the results. (a) In a random sample of 36 patients, the mean waiting time at a dentist’s office was 24 minutes and the standard deviation was 7.5 minutes. Construct a 90% confidence interval for the population mean. (b) In a random sample of 25 cereal boxes,...
Determine the area under the standard normal curve that lies between the following values. z=0.6 and...
Determine the area under the standard normal curve that lies between the following values. z=0.6 and z = 1.4 0 0.7257 0.2743 0.9192 0.1935 Assume that the random variable X is normally distributed, with mean p = 90 and standard deviation c = 12. Compute the probability P(X < 105). 0.9015 0.8944 0.8849 ОО 0.1056 The sampling distribution of the sample mean is shown. If the sample size is n = 25, what is the standard deviation of the population...
Use the standard normal distribution or the t distribution to construct a 9 % confidence interval...
Use the standard normal distribution or the t distribution to construct a 9 % confidence interval for the population mean Justify your decision if neither distribution can be used, explain why Interpret the results ln a random sample of 17 mortgage institutions, the mean interest rate was 3.69% and the standard deviation was 36% Assume the iterest rates are normally distributed Which distribution should be used to construct the confidence interval? ○ A. Use a t-distribution because it is a...
7. Determine whether a normal distribution or a normal distribution or t distribution should be used...
7. Determine whether a normal distribution or a normal distribution or t distribution should be used or whether neither of should be used to construct a confidence interval for the mean. (Section 6.2) Circle the correct answer. in a random sample of 22 families, the mean weekly food expense was $95.60 with a sample standard deviation of $22.50. Assume the weekly food expense is normally distributed. A) Normal distribution B) t-distribution C) Neither For a sample of 20 IQ scores...
Use the standard normal distribution or the t-distribution to construct a 99% confidence interval for the...
Use the standard normal distribution or the t-distribution to construct a 99% confidence interval for the population mean. Justify your decision. If neither distribution can be used, explain why. Interpret the results. In a recent season, the population standard deviation of the yards per carry for all running backs was 1.21. The yards per carry of 25 randomly selected running backs are shown below. Assume the yards per carry are normally distributed. 3.2 6.8 6.1 3.6 6.3 7.1 6.4 5.5...
Use the standard normal distribution or the t-distribution to construct a 99% confidence interval for the...
Use the standard normal distribution or the t-distribution to construct a 99% confidence interval for the population mean. Justify your decision. If neither distribution can be used, explain why. Interpret the results. In a recent season, the population standard deviation of the yards per carry for all running backs was 1.27. The yards per carry of 25 randomly selected running backs are shown below. Assume the yards per carry are normally distributed. 2.9 8.4 7.2 4.3 6.8 2.7 7.2 4.8...
Use the standard normal distribution or the t-distribution to construct a 95% confidence interval for the...
Use the standard normal distribution or the t-distribution to construct a 95% confidence interval for the population mean. Justify your decision. If neither distribution can In a recent season, the population standard deviation of the yards per carry for all running backs was 1.21. The yards per carry of 25 randomly selected running backs 2.8 be used, explain why. Interpret the results are shown below. Assume the yards per carry are normally distributed 2.7 3.7 4.7 7.1 3.7 5.9 2.5...
need help with the problems listed below
For a random sample of n = 124 U.S. cities the mean growing season length was x = 190.7 days. The population standard deviation is o = 42.8 days. Assuming the variable is normally distributed, find the 98% confidence interval (including units) of the population mean. State the distribution used. Give all digits provided by the calculator for the confidence interval. <p>Distribution used:</p> <p>Confidence interval:</p> For a sample of n = 8 randomly...
Question 6 (6 points) The average weight of n = 32 randomly selected pickup trucks was x = 7230 pounds. The population standard deviation was o = 347 pounds. Assuming the variable is normally distributed, find the 94% confidence interval (including units) of the population mean. State the distribution used. Give all digits provided by the calculator for the confidence interval. <p> Distribution used:</p> <p>Confidence interval:</p> Question 7 (6 points)
i need a clear understand how to work out the problems below.
Finding thevMean, Standard deviation, and confidence interval
The recorded high temperatures (in degrees Fahrenheit) in June for a sample of 17 US cities are listed below. Assuming the temperatures are normally distributed, find the 92% confidence interval (including units) of the population mean. Give the distribution used and the mean and standard deviation of the sample rounded to the nearest hundredth (two decimal places). Give all digits provided...
Determine the area under the standard normal curve that lies between the following values. z=0.6 and z = 1.4 0 0.7257 0.2743 0.9192 0.1935 Assume that the random variable X is normally distributed, with mean p = 90 and standard deviation c = 12. Compute the probability P(X < 105). 0.9015 0.8944 0.8849 ОО 0.1056 The sampling distribution of the sample mean is shown. If the sample size is n = 25, what is the standard deviation of the population...
Use the standard normal distribution or the t distribution to construct a 9 % confidence interval for the population mean Justify your decision if neither distribution can be used, explain why Interpret the results ln a random sample of 17 mortgage institutions, the mean interest rate was 3.69% and the standard deviation was 36% Assume the iterest rates are normally distributed Which distribution should be used to construct the confidence interval? ○ A. Use a t-distribution because it is a...
7. Determine whether a normal distribution or a normal distribution or t distribution should be used or whether neither of should be used to construct a confidence interval for the mean. (Section 6.2) Circle the correct answer. in a random sample of 22 families, the mean weekly food expense was $95.60 with a sample standard deviation of $22.50. Assume the weekly food expense is normally distributed. A) Normal distribution B) t-distribution C) Neither For a sample of 20 IQ scores...
Use the standard normal distribution or the t-distribution to construct a 99% confidence interval for the population mean. Justify your decision. If neither distribution can be used, explain why. Interpret the results. In a recent season, the population standard deviation of the yards per carry for all running backs was 1.21. The yards per carry of 25 randomly selected running backs are shown below. Assume the yards per carry are normally distributed. 3.2 6.8 6.1 3.6 6.3 7.1 6.4 5.5...
Use the standard normal distribution or the t-distribution to construct a 99% confidence interval for the population mean. Justify your decision. If neither distribution can be used, explain why. Interpret the results. In a recent season, the population standard deviation of the yards per carry for all running backs was 1.27. The yards per carry of 25 randomly selected running backs are shown below. Assume the yards per carry are normally distributed. 2.9 8.4 7.2 4.3 6.8 2.7 7.2 4.8...
Use the standard normal distribution or the t-distribution to construct a 95% confidence interval for the population mean. Justify your decision. If neither distribution can In a recent season, the population standard deviation of the yards per carry for all running backs was 1.21. The yards per carry of 25 randomly selected running backs 2.8 be used, explain why. Interpret the results are shown below. Assume the yards per carry are normally distributed 2.7 3.7 4.7 7.1 3.7 5.9 2.5...
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