Question

Problem 3: A consumer group is attempting to find whether there is a difference between three brands of flower seeds. The variable recorded is the number of seeds, out of 100 which sprouted. Six packages of seeds were used for each brand. At the .05 level is there a difference between brands? Brand 3 Brand 2 Brand 1 a) Identify the hypotheses. M M M 32 Ho: B1-B2-B, 1-V H: Ther is Betten a the differene Trands: at least I mean differs C b) Calculate the mean number that sprouted for each brand Brandi B, Brande Br Brand Bz. 566.50 X 56.17 = 85.83 X c) Fill in the ANOVA table. P-value Source Factor ssd 272.33 2 51 29.17 15 7850. 5 17 MSF 1360.665 3.972 341.945 - - 0,411 Error Total d) state your decision and conclusion. Provide justification therefore. P-vawe so.05 there ise diffrence between the brands-

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Answer 1

brand 1 brand 2 brand 3 Anova: Single Factor 44 37 70 90 100 Count 69 72 SUMMARY Groups brand 1 brand 2 brand 3 Sum Average Variance 515 85.83333 224.1667 399 66.5 447.5 337 56.16667 354.1667 90 100 a) c) null hypothesis: ul = u2 = u3 alternative hypothesis: atleast one of the mean is differ df ANOVA Source of Variation Between Groups Within Groups SS 2721.333333 5129.166667 MS F P -value 2 1360.667 3.979204 0.041079 15 341.9444 Fcrit 3.68232 brand 1 = sum/n brand 2 = brand 3 = 515/6 399/6 337/6 means 85.83 66.5 Total 7850.5 17 d) let los be alfa = 0.05 from the table, p value = 0.0411 since, p value < 0.05 we rejec the null hypothesis. we can conclude that exists difference between three brands of flower seeds.