Question

I want to calculate how much weight a Polycarbonate panel will support, for instance, If a person were to lie on top of the panel, what is the maximum weight of the person that this panel will support, before breaking. Its thickness is 1/4th inch. It has a length of 84.5 inches and a width of 12 inches. This panel is support in both of the shorter ends by an aluminum railing.

Answer 1

P.NO solution- Given - polycarbonate panel yield strength of polycarbonate Cfy] =63mpa ( standards 1 + 1 → 63% 103 kW/m2 B =12 L-84.5" > hi 84:5" 84.5% 2.54cm 214163 cm 2 2:1463M B=12 12" 12 x 2.54cm = 30.48cm = 0.30u8em Hot" 4x2.54 cm 0.635cm 0.00.635 ) support conditions not given lets consider Simply supported bondition, 845011

&x0.3048x0.00 63525 if person lie alorg breadth care (i): at central position then weight of person 11 92 84.5" BMD kwim WX21463 4 KN-M Kn-m Maximum Bending moment (m) is 2.1463 Kn-m 4 We know that oman My I Is moment of Inertia.of els where y = 1/2 I - BH3 12 # > ) max 9.1463 x BH32 126 2:1463 WXy33 2 4 BH2 tman 2 2. 1463 X3 X W omax= 261,950.523W Sand with CamScanner

o man - 261,950.523W for safe condition. oman < fy for wman - Wman oman a fy sify: 261,950.523 Wmad. 3 63x10 с юах, 0.24050 KN 261,950-523 .. Wman? 0:24050 KN Answer 240.50N if we convert into mais of person then 240.50 mass (on) Kg 9.81 rim = 24.5158 kg Answer Case Crid - If person lie along length at central. X position then ہے BMD WB kn-m Lebe B B CS Saannn with Cam Sana

In this case Н. 2 I = LH3 72 and M= WB y. WB o mare th प ter 3 WX D 3048 x 6² 24*2.1463X0.006352 romax = 5282.85 safe conditions: o max <fy oman for wman » =fy Be warned to sify = 5282-85 wmax 63x103 i. Wmax = 11:9253 KN 52 82-85 if we convert this into kg's then 1. Wmax = 11925: 3N mass A person 11925.3 7.87 1215:62kg. final Answers lima 1815:62kg les Scanned with CamScanner