a) CH3NH2 + H2O ---> CH3NH3+ + OH-
Kb = [CH3NH3+] [OH-]/[CH3NH2]
b) pH = 11.7 , pOH = 14-11.7 = 2.3
[OH-]= 10^(-2.3) = 0.005 M
0.005 = C*X
0.005 = 0.065*X
X = 0.077
Kb = cx^2
= 0.065*(0.077)^2
kb = 3.85*10^(-4)
c) ka = kw/kb = 10^(-14)/(3.85*10^(-4))
= 2.6*10^-11
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