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56) One employee is in charge of the following activities at a refreshment stand: Activity Greet customer Take order Process
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56). C-[ 20, 0.833, 3]

Processing time(in seconds)= 5+25+90+30.

=150 seconds/ customer

Seconds/hour= 60 × 60 = 3600 seconds

Process capacity= 3600÷ 150 = 24 customers/ hour

  • Flow rate= minimum(demand, process capacity). = Minimum(20 , 24) = 20 customer/ hour
  • Utilization= flow rate ÷ process capacity = 20÷ 24 = 0.833
  • Cycle time = 1 ÷ flow rate. = (1÷20)÷ 60 = 3 minutes/ customer.

58) D 184 minutes

process time( per student) = 2+ 10 + 20 = 32 minutes

Process capacity= min capacity among 3 phases

  1. 1÷ 2= 0.5
  2. 3÷10= 0.3
  3. 4 ÷ 20 = 0.2

Process capacity = 0.2 student/ minute

Flow rate= min (demand, process capacity). = Minimum(0.125, 0.2) = 0125

Cycle time= 1 ÷ flow rate. = 1÷ 0.125 8 minutes

Time to process remaining 19 students = 19 × 8 = 152 minutes

Total time to process 20 students = 152 + 32 = 184 minutes.

59) B- 0.5 hour.

time ( rush hours) = 2

Demand= 100

Capacity= 80

Waiting Time of customer arriving at 10 = Time (Demand÷ capacity- 1)

= 2(100÷80-1)

= 2(1.25 - 1)

= 0.5 hour

60) C - 1.60 hours

Time( 8 am - 4 pm)= 8 hours

Demand= 30

Capacity = 25

Waitkng time for last package to be processed = Time(demand÷ capacity - 1)

= 8(30÷ 25 - 1)

= 8(1.2 - 1)

=8(0.2)

=1.6 hours

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