56). C-[ 20, 0.833, 3]
Processing time(in seconds)= 5+25+90+30.
=150 seconds/ customer
Seconds/hour= 60 × 60 = 3600 seconds
Process capacity= 3600÷ 150 = 24 customers/ hour
58) D 184 minutes
process time( per student) = 2+ 10 + 20 = 32 minutes
Process capacity= min capacity among 3 phases
Process capacity = 0.2 student/ minute
Flow rate= min (demand, process capacity). = Minimum(0.125, 0.2) = 0125
Cycle time= 1 ÷ flow rate. = 1÷ 0.125 8 minutes
Time to process remaining 19 students = 19 × 8 = 152 minutes
Total time to process 20 students = 152 + 32 = 184 minutes.
59) B- 0.5 hour.
time ( rush hours) = 2
Demand= 100
Capacity= 80
Waiting Time of customer arriving at 10 = Time (Demand÷ capacity- 1)
= 2(100÷80-1)
= 2(1.25 - 1)
= 0.5 hour
60) C - 1.60 hours
Time( 8 am - 4 pm)= 8 hours
Demand= 30
Capacity = 25
Waitkng time for last package to be processed = Time(demand÷ capacity - 1)
= 8(30÷ 25 - 1)
= 8(1.2 - 1)
=8(0.2)
=1.6 hours
56) One employee is in charge of the following activities at a refreshment stand: Activity Greet...
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