Question

Which of the following pairs is the solution to the LP problem: min U1 + 2u2 subject to: 3u1+U227 U1+442 26 U1U220 o (u1, u2)

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Answer #1

3u1 + u2 ≥ 7 -------------> (1)

u1 + 4u2 ≥ 6 ------------- (2)

(1) *1 ---> 3u1 + u2 ≥ 7 ------------> (3)

(2) *3 ---> 3u1 + 12u2 ≥ 18 ------------> (4)

Deduct (3) from (4)

(3u1 + 12u2) - (3u1 + u2) ≥ (18-7)

11u2 ≥ 11

u2 ≥ 1

Substitute u2 in Equation 1 to get u1

3u1 + 1 ≥ 7

3u1 ≥ 6

u1 ≥ 2

Therefore, (u1 , u2) = (2,1) is correct

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