A 3 kg block slides from the top of a 3.4 m high frictionless incline. At...
A 3 kg block slides from the top of a 3.4 m high frictionless incline. At the bottom of the incline the block encounters a spring with a spring constant of 400 N/m on a horizontal surface. How far is the spring compressed?
The correct answer is 0.71 meters but I need the worked out solution!
Homework Answers
Initially block was at some vertical height so it have gravitational potential energy.
as it comes down its start converting into KE and when comes in contact with spring both KE and
PE converts into spring PE and finally all of block energy will convert into spring PE.
Using energy conservation,
mgh = kx^2 /2
(3 x 9.8 x 3.4 ) = 400x^2 /2
x = 0.707 m = 0.71 m
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