Consider the titration of 25.0 mL of 0.723M HCLO4 and 0.273M KOH. What is the H+...
Consider the titration of 25.0 mL
of 0.723M HCLO4 and 0.273M KOH. What is the H+ concentration after
the addition of 80.0 mL of KOH?
Please show and explain all steps thoroughly!
Homework Answers
Reaction between KOH and HClO4:
KOH + HClO4
KClO4 + H2O
Moes of HClO4 = Volume (in L) x molarity = 0.025 x 0.723 = 0.01807 moles
Moles of KOH added = 0.080 x 0.273 = 0.02184 moles
As we can see number of moles of KOH exceeds number of moles of HClO4. It means all the HClO4 has been consumed. Concentration of H+ ions is zero after addition 80 ml of KOH.
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