Question

Question 2 25 points Save Answer Problem Solving #2. (Finding a Job Through Networking in a survey of randomly selected 40 workers, to the question what is the strategy for finding jobs after graduation?. their answers are given as follows: N-Networking R-Regular application A Advertisement 0Other means TRN N NON ANNNN O NA NRN N N N N N N N N N N (a) What is the underlying population of interest? What is the variable is the variable qualitative or quantitative? What is the highest level of measurement can be used for this data? (b) Construct a frequency table including relative frequencies in percent (%) What strategy is most useful? (c) Use the sample data with a 0.03 significance level to test the claim that most more than 50%) workers get their jobs through networking recently. What does the result Suggest about the strategy for find a job after graduation? Hint: Run a hypothesis test using the steps: Step Write the null and alternative hypotheses in symbolic form Step 2: Check the requirements Step 3. Determine the mean and standard deviation of the sampling distribution of the sample statistic what test statistic should be used assuming the hypothesis is true Step 4. Determine the type of test, the critical value and sketch the rejection region Step 5. Calculate the sample statistic value Step 6. State your conclusion in plain English TTT Arta 31200 T-3. E-

Answer 1

Solution:- a) The graduates who cell apply for cook are the population of interest The veciable is strategy for finding job after goraduation The variable is cualitative The highest level of meascament is nominal. b) To Constellect a fequency table including selative facequencies in present (7.) what stocategy is most wettel :- 1 Category 1 Frequency | Relative frequency 1 % 0.675 0.15 67,5 15.0 10.0 7:50 0.10 0.075 100.0 Tatal Nekroosting 1,00 strategy is the most useful c) step : 1 Ho : Null Hypothesis: - p <0.g. (not more than 50y, workers get Their jobs thoroughs rebooring). Ha Altanative hypothests '- p>0,5 (more than sol.coorkers get their jobs horcon through netvorichig).

step:- 2 n=40 , Po=0.5 P- 27/40 =0.675 mp = 4010.675) ci mp'=9730 n(1-P) = 40(1-0.675) = 40(0.305) - 13710 both conditions are satisfied. step:-3 Mean of samping distribution =-0675 standard deviation of samping distaci bulion is geven by: -Bo (1-P) (9.5x11-05) - 0.0791 orn 40 . step-H 2 - Test for one sample proportions ; 2= 0.03 From the table Critical value of Z=1.88 pejection region, Reject to if z is greater than 1.88 stepis . Test statistic is given by : Pl_Po 0.675 -0.50 Pollo) To.so x (1-0.50)/40 Z vn

s 0145 Jo.000625 0.175 0.079056 1. 7 = 2.214 step: 6 since calulated value of 2=2.214 is greath flan Cautical value of 2=1.88. The difference is significant : Reject Nail Hypothesis. Concicesion' - Joy. The data sepport to claim that maore than COYK && get tirer jobs teough Networking