In this combustion reaction, one mole C10H8 react with 12 mole O2 to form 10 mole CO2 and 4 mole H2O produced and heat released = 5157 KJ
we have
790 g CO2 are formed.
thus
moles of CO2 = mass / molar mass = 790 g / 44.01 g / mole = 17.95 mole.
thus
delta H = 5157 * 17.95 / 10 = 9256.815 KJ = 9256815 J
(delta n)g = moles of gaseous product - moles of gaseous reactant = (10 - 12) = -2
we know,
delta H = delta E + (delta n)g * RT
or
9256815 = delta E + (-2 * 8.314 * 350)
or
delta E = 9262634.8 J = 9262.6 KJ
or
delta E = 9262.6 KJ
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