the pattern of inheritance is Incomplete dominance.
let the alleles be B- black, W- white.
then let`s do the crosses and check the proportion of progenies.
BB- Black, WW- white, BW- Gray
1) Gray * gray
BW * BW
B | W | |
B | BB ( black) | BW ( gray) |
W | BW ( gray) | WW ( white) |
expected proportion is black= number of black/total number=1/4
the expected proportion of Gray= number of Gray/total number=2/4=1/2
expected proportion of white= number of white/total number=1/4
2) Black * black
BB * BB
BB ( F1)
all the F1 progenies are black.
3) WW * WW
WW ( F1)
all the F1 progenies are white.
4) Black * gray
BB * BW
B | W | |
B | BB ( black) | BW ( gray) |
expected proportion is black= number of black/total number=1/2
the expected proportion of Gray= number of Gray/total number=1/2
5) white * gray
WW * BW
B | W | |
W | BW ( Gray) | WW ( white) |
expected proportion is white= number of white/total number=1/2
the expected proportion of Gray= number of Gray/total number=1/2
6) Black * white
BB * WW
BW
all the F1 progenies are Gray
expected proportions in all crosses are same as the observed proportions so the pattern of inheritance is incomplete dominance and one gene controls the phenotype, the gene has 2 alleles.
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